Assume that females have pulse rate that are normally distribute with a mean 74.0 beats per minute and a standard deviation of 12.5 beats per minute. If 16 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 80 beats per minute.
0.4988
0.0012
0.0274
0.9726
Solution :
Given that,
mean = = 74
standard deviation = = 12.5
n = 16
= 74
= / n = 12.5/ 16=3.125
P( < 80) = P[( - ) / < (80-74) / 3.125]
= P(z <1.92 )
Using z table
=0.9726
probability=
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