A data set includes data from student evaluations of courses. The summary statistics are nequals94, x overbarequals4.17, sequals0.63. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Solution :
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 4.25
Ha : 4.25
Test statistic = z
= ( - ) / / n
= (4.17 - 4.25) / 0.63 / 94
= -1.23
P(z < -1.23) = 0.1093
P-value = 0.1093
= 0.01
P-value >
Fail to reject the null hypothesis .
There is not sufficient evidence to that claim in population of student course evaluations has a mean equal to 4.25 .
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