A random sample of 225 1st-year statistics tutorials was selected from the past 5 years and the number of students absents recorded. The results were a population mean of 11.6 with a standard deviation of 4.1 absences. Find the Confidence Interval of absences over the past 5 years with 90% confidence.
Solution :
Given that,
Sample size = n = 225
Z/2 = 1.645
Margin of error = E = Z/2* ( /n)
= 1.645 * (4.1 / 225)
Margin of error = E = 0.4
At 90% confidence interval estimate of the population mean is,
- E < < + E
11.6 - 0.4 < < 11.6 + 0.4
11.2 < < 12
(11.2 , 12)
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