Over a long period of time, a pharmacy has found that 68% of transactions on a Saturday are paid for by credit card. If 119 customers come into the pharmacy on a normal Saturday morning, what is the approximate probability that more than 71% of transactions are paid for by credit card
0.758 |
||
0.512 |
||
0.242 |
||
0.488 |
||
0.627 |
Solution :
Given that ,
p = 0.68
1 - p = 0.32
n = 119
= p = 0.68
= (p*(1-p))/n = (0.68*0.32)/119 = 0.04276
P( > 0.71) = 1 - P( < 0.71)
= 1 - P(( - ) / < (0.71-0.68) /0.04276 )
= 1 - P(z < 0.70)
= 1 - 0.758
= 0.242
Probability = 0.242
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