Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Round your answers to four decimal places.)
(e) P(Z ≤ 1.43)
(h) P(1.43 ≤ Z ≤ 2.50)
Solution :
Given that,
Using standard normal table ,
(e)
P(z 1.43) = 0.9236
(h)
P(1.43 z 2.50)
= P(z 2.50) - P(z 1.43)
= 0.9938 - 0.9236
= 0.0702
P(1.43 z 2.50) = 0.0702
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