Question

Each person in a large sample of German adolescents was asked to indicate which of 50 popular movies they had seen in the past year. Based on the response, the amount of time (in minutes) of alcohol use contained in the movies the person had watched was estimated. Each person was then classified into one of four groups based on the amount of movie alcohol exposure (groups 1, 2, 3, and 4, with 1 being the lowest exposure and 4 being the highest exposure). Each person was also classified according to school performance. The resulting data is given in the accompanying table.

Assume it is reasonable to regard this sample as a random sample of German adolescents. Is there evidence that there is an association between school performance and movie exposure to alcohol? Carry out a hypothesis test using

α = 0.05.

		Alcohol Exposure Group
		1	2	3	4
School Performance	Excellent	111	93	49	67
	Good	329	326	317	297
	Average/Poor	239	259	314	319

Calculate the test statistic. (Round your answer to two decimal places.)
χ² =

What is the P-value for the test? (Round your answer to four decimal places.)
P-value =

Answer 1

SOL:-

Results
	1	2	3	4		Row Totals
excellent	111  (79.88)  [12.12]	93  (79.76)  [2.20]	49  (80.00)  [12.01]	67  (80.35)  [2.22]		320
good	329  (316.78)  [0.47]	326  (316.32)  [0.30]	317  (317.25)  [0.00]	297  (318.65)  [1.47]		1269
average/poor	239  (282.33)  [6.65]	259  (281.92)  [1.86]	314  (282.75)  [3.45]	319  (284.00)  [4.31]		1131
Column Totals	679	678	680	683		2720  (Grand Total)

a) chi square test statistic

DF=6,

b)

p-value = 0.00001

The result is significant at p < .05.