Question

In a random sample of 38 criminals convicted of a certain​ crime, it was determined that...

In a random sample of

38

criminals convicted of a certain​ crime, it was determined that the mean length of sentencing was

55

​months, with a standard deviation of

8

months. Construct and interpret a

95​%

confidence interval for the mean length of sentencing for this crime.Click here to view the standard normal distribution table (page 1).

LOADING...

Click here to view the standard normal distribution table (page 2).

LOADING...

Click here to view the table of critical t-values.

LOADING...

Select the correct choice below and fill in the answer boxes to complete your choice.

​(Use ascending order. Round to one decimal place as​ needed.)

A.There is a

95​%

probability that the mean length of sentencing for the crime is between

nothing

and

nothing

months.

B.

95​%

of the sentences for the crime are between

nothing

and

nothing

months.

C.We can be

95%

confident that the mean length of sentencing for the crime is between

nothing

and

nothing

months.

Homework Answers

Answer #1

t critical value at 0.05 significance level with 37 df = 2.026

95% confidence interval for is

- t * S / sqrt(n) < < + t * S / sqrt(n)

55 - 2.026 * 8 / sqrt(38) < < 55 + 2.026 * 8 / sqrt(38)

52.4 < < 57.6

95% CI is (52.4 , 57.6)

We can be 95% confident that the mean length of sentencing for a crime is between 52.4 and 57.6 months.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a random sample of 37 criminals convicted of a certain​ crime, it was determined that...
In a random sample of 37 criminals convicted of a certain​ crime, it was determined that the mean length of sentencing was 57 ​months, with a standard deviation of 12 months. Construct and interpret a 90​% confidence interval for the mean length of sentencing for this crime. Select the correct choice below and fill in the answer boxes to complete your choice. ​(Use ascending order. Round to one decimal place as​ needed.) A. There is a 90​% probability that the...
In a random sample of 39 criminals convicted of a certain​ crime, it was determined that...
In a random sample of 39 criminals convicted of a certain​ crime, it was determined that the mean length of sentencing was 61 ​months, with a standard deviation of 14 months. Construct a 95​% confidence interval for the mean length of sentencing for this crime. The 95​% confidence interval is ​(?,?).
In a random sample of 36 criminals convicted of a certain​ crime, it was determined that...
In a random sample of 36 criminals convicted of a certain​ crime, it was determined that the mean length of sentencing was 57 ​months, with a standard deviation of 10 months. Construct and interpret a 95​% confidence interval for the mean length of sentencing for this crime.
In a random sample of 81 audited estate tax​ returns, it was determined that the mean...
In a random sample of 81 audited estate tax​ returns, it was determined that the mean amount of additional tax owed was ​$3477 with a standard deviation of ​$2512. Construct and interpret a​ 90% confidence interval for the mean additional amount of tax owed for estate tax returns. Click here to view the standard normal distribution table (page 1) Click here to view the standard normal distribution table (page 2) Click here to view the table of critical t-values. Find...
In a survey of 10101010 ​adults, a polling agency​ asked, "When you​ retire, do you think...
In a survey of 10101010 ​adults, a polling agency​ asked, "When you​ retire, do you think you will have enough money to live comfortably or not. Of the 10101010 ​surveyed, 532532 stated that they were worried about having enough money to live comfortably in retirement. Construct a 9090​% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement. Click here to view the standard normal distribution table (page 1). LOADING... Click...
A random sample of 1016 adults in a certain large country was asked? "Do you pretty...
A random sample of 1016 adults in a certain large country was asked? "Do you pretty much think televisions are a necessity or a luxury you could do? without?" Of the 1016 adults? surveyed, 533 indicated that televisions are a luxury they could do without. Complete parts? (a) through? (c) below. Click here to view the standard normal distribution table (page 1). LOADING... Click here to view the standard normal distribution table (page 2). LOADING... ?(a) Obtain a point estimate...
A random sample of 1021 adults in a certain large country was asked "Do you pretty...
A random sample of 1021 adults in a certain large country was asked "Do you pretty much think televisions are a necessity or a luxury you could do without?" Of the 1021 adults surveyed, 511 indicated that televisions are a luxury they could do without. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). LOADING... Click here to view the standard normal distribution table (page 2). LOADING... (a) Obtain a point estimate...
Using the simple random sample of weights of women from a data​ set, we obtain these...
Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics: nequals40 and x overbarequals153.03 lb. Research from other sources suggests that the population of weights of women has a standard deviation given by sigmaequals30.91 lb. a. Find the best point estimate of the mean weight of all women. b. Find a 90​% confidence interval estimate of the mean weight of all women. Click here to view a t distribution table. LOADING... Click...
A survey of 2315 adults in a certain large country aged 18 and older conducted by...
A survey of 2315 adults in a certain large country aged 18 and older conducted by a reputable polling organization found that 416 have donated blood in the past two years. Complete parts (a)and (b) below. Click here to view the standard normal distribution table (page 1). LOADING... Click here to view the standard normal distribution table (page 2). LOADING... (a) Obtain a point estimate for the population proportion of adults in the country aged 18 and older who have...
Using the simple random sample of weights of women from a data​ set, we obtain these...
Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics: nequals40 and x overbarequals144.09 lb. Research from other sources suggests that the population of weights of women has a standard deviation given by sigmaequals32.28 lb. a. Find the best point estimate of the mean weight of all women. b. Find a 95​% confidence interval estimate of the mean weight of all women. Click here to view a t distribution table. LOADING... Click...