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Question 1 2 pts
(CO6) From a random sample of 55 businesses, it is found that the mean time that employees spend on personal issues each week is 4.9 hours with a standard deviation of 0.35 hours. What is the 95% confidence interval for the amount of time spent on personal issues?
(4.84, 4.96) |
(4.83, 4.97) |
(4.81, 4.99) |
(4.82, 4.98) |
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Question 2 2 pts
(CO6) If a confidence interval is given from 8.54 to 10.21 and the mean is known to be 9.375, what is the margin of error?
8.540 |
0.835 |
1.670 |
0.418 |
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Question 3 2 pts
(CO6) Which of the following is most likely to lead to a small margin of error?
small standard deviation |
large margin of error |
small mean |
large sample size |
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Question 4 2 pts
(CO6) From a random sample of 41 teens, it is found that on average they spend 31.8 hours each week online with a standard deviation of 5.91 hours. What is the 90% confidence interval for the amount of time they spend online each week?
(30.62, 32.99) |
(25.89, 37.71) |
(29.99, 33.61) |
(30.28, 33.32) |
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Question 5 2 pts
(CO6) A company making refrigerators strives for the internal temperature to have a mean of 37.5 degrees with a standard deviation of 0.6 degrees, based on samples of 100. A sample of 100 refrigerators have an average temperature of 37.70 degrees. Are the refrigerators within the 90% confidence interval?
No, the temperature is outside the confidence interval of (36.90, 38.10) |
No, the temperature is outside the confidence interval of (37.40, 37.60) |
Yes, the temperature is within the confidence interval of (37.40, 37.60) |
Yes, the temperature is within the confidence interval of (36.90, 38.10) |
1)
Solution :
Given that,
Point estimate = sample mean = = 4.9
Population standard deviation = = 0.35
Sample size = n = 55
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (0.35 / 55)
= 0.09
At 95% confidence interval estimate of the population mean is,
- E < < + E
4.9 - 0.09 < < 4.9 + 0.09
4.81 < < 4.99
(4.81 , 4.99 )
2)
Given that,
Lower confidence interval = 8.54
Upper confidence interval = 10.21
= 9.375
Margin of error = E = Upper confidence interval - = 10.21 - 9.375 = 0.835
Margin of error = 0.835
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