Run a regression analysis on the following bivariate set of data with y as the response variable.
x | y |
---|---|
81.1 | 86 |
77.5 | 60.4 |
92.7 | 126.5 |
104 | 132.5 |
85 | 53.1 |
64.3 | 95.5 |
64.6 | 31.7 |
39.7 | 5.7 |
82.3 | 121.3 |
82.4 | 98.2 |
29.2 | -50.2 |
34.2 | -1 |
Find the correlation coefficient and report it accurate to three
decimal places.
r =
What proportion of the variation in y can be explained by
the variation in the values of x? Report answer as a
percentage accurate to one decimal place. (If the answer is
0.84471, then it would be 84.5%...you would enter 84.5 without the
percent symbol.)
r² = %
Based on the data, calculate the regression line (each value to
three decimal places)
y = x +
Predict what value (on average) for the response variable will be
obtained from a value of 87 as the explanatory variable. Use a
significance level of α=0.05 to assess the strength of the linear
correlation.
What is the predicted response value? (Report answer accurate to
one decimal place.)
y =
The given data is inputted in EXCEL, post which the SCATTERPLOT function is used to obtain the scatter plot and then the TRENDLINE function is used to obtain the regression equation here as:
The correlation coefficient now is computed here as:
Therefore 0.903 is the required correlation coefficient here.
As the coefficient of determination here is 0.8156, therefore 81.56% of the variation in the in y can be explained by the variation in x here.
The regression equation can be seen from the plot here as:
Now the predicted value here is computed as:
Therefore 100.7 is the required predicted value here.
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