6. A sample of 200 body temperatures of adults has a mean temperature of 98.10◦F. Suppose the population standard deviation is 0.62◦F. Use a 0.05 significance level to test the claim that the mean body temperature of all adults is equal to 98.6◦F as is commonly believed. Fill in the following information as you test the above claim: State the claim symbolically and the opposite of the claim.
H0 :
H1 :
Teststatistic: |
P-value: |
Conclusion: |
6)
Solution :
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 98.6
Ha : 98.6
Test statistic = z
= ( - ) / / n
= (98.10 - 98.6) / 0.62 / 200
= -11.40
P(z < -11.40) = 0
P-value = 2 * 0 = 0
= 0.05
P-value <
Reject the null hypothesis .
There is sufficient evidence to the claim that the mean body temperature of all adults is equal to 98.6◦F .
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