A hospital reported that the normal death rate for patients with
extensive burns (more than 40% of skin area) has been significantly
reduced by the use of new fluid plasma compresses. Before the new
treatment, the mortality rate for extensive burn patients was about
60%. Using the new compresses, the hospital found that only 44 of
93 patients with extensive burns died. Use a 1% level of
significance to test the claim that the mortality rate has dropped
since using the new treatment.
a. What are we testing in this problem?
single proportion
single mean
b. What is the level of significance?
c. State the null and alternate hypotheses.
H0: p ≤ 0.6; H1: p > 0.6
H0: p ≥ 0.6; H1: p < 0.6
H0: μ ≥ 0.6; H1: μ < 0.6
H0: μ ≤ 0.6; H1: μ > 0.6
H0: μ = 0.6; H1: μ ≠ 0.6
H0: p = 0.6; H1: p ≠ 0.6
d. What sampling distribution will you use?
The Student's t.
The standard normal.
e. What is the value of the sample test statistic? (Round
your answer to two decimal places.)
f. Estimate the P-value.
P-value > 0.250
0.125 < P-value < 0.250
0.050 < P-value < 0.125
0.025 < P-value < 0.050
0.005 < P-value < 0.025
P-value < 0.005
g. Will you reject or fail to reject the null hypothesis?
Are the data statistically significant at level
α?
At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant.
At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant.
At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant.
At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
h. Interpret your conclusion in the context of the
application.
There is sufficient evidence at the 0.01 level to conclude that the mortality rate has dropped.
There is insufficient evidence at the 0.01 level to conclude that the mortality rate has dropped
a) Single proportion
b) The level of significance is 0.01
c) H0: p < 0.6
H1: p > 0.6
d) the standard normal.
e) = 44/93 = 0.4731
The test statistic is
f) P-value = P(Z < -2.50)
= 0.0062
0.005 < P-value < 0.025
g) Since the P-value is less than the significance level(0.0062 < 0.01), so we should reject the null hypothesis.
At the = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant.
h) There is sufficient evidence at the 0.01 level to conclude that the mortality rate has dropped.
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