Suppose the mean pulse rate of college students is 68 beats per minute with a standard deviation of 11.5. You conduct a special exercise program for 37 college students. After completing the program, the mean pulse rate of the students was 64.4. Test the hypothesis that the program lowered students’ pulse rates using a = 0.01.
Solution :
This is the left tailed test .
The null and alternative hypothesis is ,
H0 : = 68
Ha : < 68
Test statistic = z
= ( - ) / / n
= (64.4 - 68) /11.5 / 37
= -1.90
P(z < -1.90) = 0.0287
P-value = 0.0287
= 0.01
P-value >
Fail to reject the null hypothesis .
Get Answers For Free
Most questions answered within 1 hours.