A genetic experiment with peas resulted in one sample of offspring that consisted of
green peas and
yellow peas.a. Construct a
confidence interval to estimate of the percentage of yellow peas.
b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?
a. Construct a
confidence interval. Express the percentages in decimal form.
Sample proportion = 154 / (154 + 418) = 154 / 572 = 0.269
95% confidence interval for p is
- Z * sqrt( ( 1 - ) / n) < p < + Z * sqrt( ( 1 - ) / n)
0.269 - 1.96 * sqrt( 0.269 * 0.731 / 572 ) < p < 0.269 + 1.96 * sqrt( 0.269 * 0.731 / 572 )
0.233 < p < 0.305
95% CI is ( 0.233 , 0.305 )
Since claimed proportion 0.25 lies in confidence interval calculated in part a) , we do not have
sufficient evidence to reject the null hypothesis.
The result does not contradict the expectation.
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