Suppose a large shipment of microwave ovens contained 14% defectives. If a sample of size 278 is selected, what is the probability that the sample proportion will differ from the population proportion by less than 5%? Round your answer to four decimal places.
Solution :
Given that ,
p = 14% = 0.14
1 - p = 1- 0.14 = 0.86
n = 278
= p = 0.14
= (p*(1-p))/n = (0.14*0.86)/278 = 0.02081
P(0.09 < < 0.19)
P(0.9 < <0. 19) = P((0.9-0.14)/0.02081 ) < ( - ) / < (0.19-0.14) /0.02881 ) )
= P(-2.403 < z < 2.403 )
= P(z < 2.403) - P(z < -2.403)
= 0.9919 - 0.0081
= 0.9838
Probability = 0.9838
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