Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test.
Upper H 0 : p = 0.89 versus Upper H 1 : p not equals 0.89
n=500, x=430, a=0.01
Now find p ^ (Type an integer or a decimal. Do not round.)
Find the test statistic z0. (Type an integer or a decimal. Do not round.)
Find P-value (Type an integer or a decimal. Do not round.)
Solution :
Given that,
= 0.89
1 - = 0.11
n = 500
x = 430
Level of significance = = 0.01
Point estimate = sample proportion = = x / n =430 / 500 = 0.86
This a two tailed test.
Test statistics
z = ( - ) / *(1-) / n
= ( 0.86 - 0.89) / (0.89*0.11) / 500
= -2.14
P-value = 2*P(Z<z)
= 2*P(Z <-2.14 )
=2*0.0162
= 0.0324
The p-value is p =0.0324, and since p = 0.0324 > 0.01, it is concluded that the null hypothesis is not rejected.
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