Question

n the game of​ roulette, a player can place a ​$1010 bet on the number 2121 and have a StartFraction 1 Over 38 EndFraction 1 38 probability of winning. If the metal ball lands on 2121​, the player gets to keep the ​$1010 paid to play the game and the player is awarded an additional ​$350350. ​ Otherwise, the player is awarded nothing and the casino takes the​ player's ​$1010. What is the expected value of the game to the​ player? If you played the game 1000​ times, how much would you expect to​ lose? The expected value is ​$nothing. ​(Round to the nearest cent as​ needed.) The player would expect to lose about ​$nothing. ​(Round to the nearest cent as​ needed.)

Answer 1