The weights of four randomly and independently selected bags of tomatoes labeled 5.0 pounds were found to be 5.1, 5.0, 5.1, and 5.2 pounds. Assume Normality. Answer parts (a) and (b) below.
a. Find a 95% confidence interval for the mean weight of all bags of tomatoes.
Confidence interval for Population mean is given as below:
Confidence interval = Xbar ± t*S/sqrt(n)
From given data, we have
Xbar = 5.1
S = 0.081649658
n = 4
df = n – 1 = 3
Confidence level = 95%
Critical t value = 3.1824
(by using t-table)
Confidence interval = Xbar ± t*S/sqrt(n)
Confidence interval = 5.1 ± 3.1824*0.081649658/sqrt(4)
Confidence interval = 5.1 ± 0.1299
Lower limit = 5.1 - 0.1299 = 4.97
Upper limit = 5.1 + 0.1299 = 5.23
Confidence interval = (4.97, 5.23)
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