Question

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Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was

72.2 Mbps. The complete list of 50 data speeds has a mean of x =16.02 Mbps and a standard deviation of s=30.03 Mbps.

a.What is the difference between carrier's highest data speed and the mean of all 50 data speeds?

b. How many standard deviations is that [the difference found in part (a)]?

c. Convert the carrier's highest data speed to a z score.

d. If we consider data speeds that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?

Answer 1

a.What is the difference between carrier's highest data speed and the mean of all 50 data speeds?
=(72.2 - 16.02) = 56.18

b. How many standard deviations is that [the difference found in part (a)]?
=56.18/30.03
=1.87079

c. Convert the carrier's highest data speed to a z score.
z = (X - mu)/sd
= 1.87079

d. If we consider data speeds that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
Not significant , since -2 < 1.87079 < 2

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