Question

The calculations for a factorial experiment involving four levels of factor A, three levels of factor...

The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following data: SST= 248, SSA= 22, SSB= 21, SSAB= 155.

Set up the ANOVA table and test for significance using alpha= .05 . Show entries to 2 decimals, if necessary. If the answer is zero enter “0”.

Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value
Factor A
Factor B
Interaction
Error
Total

Homework Answers

Answer #1

Level of factor A, a = 4

Level of factor B,b = 3

Replications, r = 3

Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value
Factor A 22 a-1 = 3

22/3

= 7.3333

7.333/2.0833

= 3.52

F.DIST.RT(3.52, 3, 24)

= 0.0303

Factor B 21 b-1 = 2

21/2

= 10.5

10.5/2.0833

= 5.04

F.DIST.RT(5.04, 2, 24)

= 0.0149

Interaction 155 (a-1)*(b-1) = 6

155/6

= 25.8333

25.8333/2.0833

= 12.4

F.DIST.RT(12.4, 6, 24)

= 0.0000

Error

248 -22-21-155

= 50

ab(r-1) = 24

50/24

= 2.0833

Total 248 abr -1 = 35
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