Question

The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following data: SST= 248, SSA= 22, SSB= 21, SSAB= 155.

Set up the ANOVA table and test for significance using alpha= .05 . Show entries to 2 decimals, if necessary. If the answer is zero enter “0”.

Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F |
p-value |

Factor A | |||||

Factor B | |||||

Interaction | |||||

Error | |||||

Total |

Answer #1

Level of factor A, a = 4

Level of factor B,b = 3

Replications, r = 3

Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square |
F |
p-value |

Factor A | 22 |
a-1 = 3 |
22/3 = |
7.333/2.0833 = |
F.DIST.RT(3.52, 3, 24) = |

Factor B | 21 |
b-1 = 2 |
21/2 = |
10.5/2.0833 = |
F.DIST.RT(5.04, 2, 24) = |

Interaction | 155 |
(a-1)*(b-1) = 6 |
155/6 = |
25.8333/2.0833 = |
F.DIST.RT(12.4, 6, 24) = |

Error |
248 -22-21-155 = |
ab(r-1) = 24 |
50/24 = |
||

Total | 248 |
abr -1 = 35 |

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Set up the ANOVA table and test for significance
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Round p-value to four decimal places. If your answer is
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Set up the ANOVA table and test for significance using a=.05.
Show entries to 2 decimals, if necessary. If the answer is zero
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