Question

An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). If answer is zero enter "0".

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F	p-value
Treatments	700
Blocks	400
Error
Total	1,500

Use alpha= .05 to test for any significant differences.

Answer 1

The given ANOVA Table is completed as follows:

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F	p - value
Treatments	700	4-1=3	700/3=233.33	233.33/19.05=12.25	0.0001
Blocks	400	8-1=7	400/7=57.14	57.14/19.05=3.00	0.0239
Error	400	32-4-8+1=21	400/21=19.05
Total	1500	32-1=31

For Treatments:

F = 233.33/19.05=12.25

Degrees of Freedom = (3,21). By Technology, p - value = 0.0001

Since p - value = 0.0001 is less than = 0.05, the difference is significant. Reject null hypothesis.

For Blocks:

F = 57.14/19.05=3.00

Degrees of Freedom = (7,21). By Technology, p - value = 0.0239

Since p - value = 0.0239 is less than = 0.05, the difference is significant. Reject null hypothesis.