Question

Lack of sleep costs companies about $18 billion a year in lost productivity according to the...

  1. Lack of sleep costs companies about $18 billion a year in lost productivity according to the National Sleep Foundation. Companies are waking up to the problem, however. Some even have quiet rooms available for study or sleep. “Power naps” are in vogue (Athens Daily News, Jan. 9, 2000). A major airline recently began encouraging reservation agents to nap during their breaks. The table below lists the number of complaints during the 6 months before naps were encouraged and during the 6 months after the policy change. Does this give evidence that the new napping policy reduced the mean number of customer complaints about reservation agents? Use a 5% significance level.

Number of Customer Complaints

Agent

1

2

3

4

5

6

7

8

9

10

Before Policy

10

3

16

11

8

2

1

14

5

6

After Policy

5

0

7

4

6

4

2

3

5

1

Diff (Before – After)

-5

-3

-9

-7

-2

2

1

-11

0

-5

  1. State the null (H0) and alternate (HA) hypotheses.

Ho: µd = 0

Ha: µ d < 0

  1. Check the assumptions

  1. Give the test statistic.
  1. Give the P-value and the conclusion reached about the null hypothesis based on the P-value.
  1. Summarize the final conclusion in the context of the claim.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
4a.) The management of a hotel is worried about the number of customer complaints. A detail...
4a.) The management of a hotel is worried about the number of customer complaints. A detail analysis shows the number of complaints in 100 feedback per week over the past 12 weeks. a) Develop control charts with z = 3. b) Is the process in control? Week Number of complaints 1 4 2 5 3 6 4 6 5 3 6 2 7 6 8 7 9 3 10 4 11 3 12 4
18. A study examines the relationship between hours of sleep and the level of relaxation one...
18. A study examines the relationship between hours of sleep and the level of relaxation one feels in the afternoon in a SAMPLE of women. One group was allowed to sleep between 5 and 6 hours and the other group was allowed to sleep between 7 and 8 hours. Here are the data for both groups:             5-6 hours of sleep                                7-8 hours of sleep                   4, 1, 5, 10, 5, 10                                    3, 2, 9, 15, 1, 12 Calculate the...
The customer service manager of a company has tracked the number of customer complaints that she...
The customer service manager of a company has tracked the number of customer complaints that she has received each day for the last 25 days. The data is: 0 complaints, 1 day 1 complaint, 2 days 2 complaints, 0 days 3 complaints, 2 days 4 complaints, 4 days 5 complaints, 1 day 6 complaints, 3 days 7 complaints, 3 days 8 complaints, 5 days 9 complaint, 3 days 10 complaints, 1 day Based on this probability distribution, calculate: The probability...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 95% confidence interval for the true difference in hours of sleep between...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 90% confidence interval for the true difference in hours of sleep between...
10 students report the number of hours of sleep they had the night before a test...
10 students report the number of hours of sleep they had the night before a test X. The info below reports the results and the answers correctly are shown as Y Student Hours Sleep (X) No. Correct (Y) 1 3 5 2 1 4 3 5 13 4 6 15 5 1 3 6 2 6 7 4 10 8 3 11 9 3 9 10 5 11 A) calculate the y-intercept of the regression line for these data. a)...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 90% confidence interval for the true difference in hours of sleep between...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 90% confidence interval for the true difference in hours of sleep between...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 95% confidence interval for the true difference in hours of sleep between...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 80% confidence interval for the true difference in hours of sleep between...