a normally distributed population has mean 57.7 and standard deviation 12.1 .(a) find the probability that single randomly selected element X OF THE POPULATION IS LESS THAN 45 (b) find the mean and standard deviation of x for samples size 16. (c) find the probability that the mean of a sample of size 16 drawn from this population is less than 45
Solution :
Given that ,
mean = = 57.7
standard deviation = = 12.1
n = 16
_{} = 57.7
_{} = / n = 12.1 / 16 = 3.024
P( < 45) = P(( - _{} ) / _{} < (45 - 57.7) / 3.025)
= P(z < -4.20)
= 0
Get Answers For Free
Most questions answered within 1 hours.