a normally distributed population has mean 57.7 and standard deviation 12.1 .(a) find the probability that single randomly selected element X OF THE POPULATION IS LESS THAN 45 (b) find the mean and standard deviation of x for samples size 16. (c) find the probability that the mean of a sample of size 16 drawn from this population is less than 45
Solution :
Given that ,
mean =
= 57.7
standard deviation =
= 12.1
n = 16
= 57.7
=
/
n = 12.1 /
16 = 3.024
P(
< 45) = P((
-
) /
< (45 - 57.7) / 3.025)
= P(z < -4.20)
= 0
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