Question

It is commonly believed that the mean body temperature of a
healthy adult is 98.6∘F. You are not entirely convinced. You
believe that it is not 98.6∘F. You collected data using 54 healthy
people and found that they had a mean body temperature of 98.26∘F
with a standard deviation of 1.16∘F. Use a 0.05 significance level
to test the claim that the mean body temperature of a healthy adult
is not 98.6∘F.

**a)** Identify the null and alternative
hypotheses?

H0: ?

H1: ?

**b)** What type of hypothesis test should you conduct
(left-, right-, or two-tailed)?

- left-tailed
- right-tailed
- two-tailed

**c)** Identify the appropriate significance
level.

**d)** Calculate your test statistic. Write the result
below, and be sure to round your final answer to two decimal
places.

**e)** Calculate your p-value. Write the result below,
and be sure to round your final answer to four decimal
places.

**f)** Do you reject the null hypothesis?

- We reject the null hypothesis, since the p-value is less than the significance level.
- We reject the null hypothesis, since the p-value is not less than the significance level.
- We fail to reject the null hypothesis, since the p-value is less than the significance level.
- We fail to reject the null hypothesis, since the p-value is not less than the significance level.

**g)** Select the statement below that best represents
the conclusion that can be made.

- There is sufficient evidence to warrant rejection of the claim that the mean body temperature of a healthy adult is not 98.6∘F.
- There is not sufficient evidence to warrant rejection of the claim that the mean body temperature of a healthy adult is not 98.6∘F.
- The sample data support the claim that the mean body temperature of a healthy adult is not 98.6∘F.
- There is not sufficient sample evidence to support the claim that the mean body temperature of a healthy adult is not 98.6∘F.

Answer #1

a)

Below are the null and alternative Hypothesis,

Null Hypothesis, H0: μ = 98.6

Alternative Hypothesis, Ha: μ ≠ 98.6

b)

two tailed

c)

0.05

d)

Test statistic,

t = (xbar - mu)/(s/sqrt(n))

t = (98.26 - 98.6)/(1.16/sqrt(54))

t = -2.15

e)

P-value Approach

P-value = 0.0361

As P-value < 0.05, reject the null hypothesis.

f)

We reject the null hypothesis, since the p-value is less than the significance level.

g)

There is sufficient evidence to warrant rejection of the claim
that the mean body temperature of a healthy adult is not
98.6∘F.

It is commonly believed that the mean body temperature of a
healthy adult is 98.6∘F98.6∘F. You are not entirely convinced. You
believe that it is not 98.6∘F98.6∘F. You collected data using 54
healthy people and found that they had a mean body temperature of
98.22∘F98.22∘F with a standard deviation of 1.17∘F1.17∘F. Use a
0.05 significance level to test the claim that the mean body
temperature of a healthy adult is not 98.6∘F98.6∘F.
a) Identify the null and alternative
hypotheses?
H0H0: (p...

It is commonly believed that the mean body temperature
of a healthy adult is F.
You
are not entirely convinced; you believe that it is not
F
a)
If you going to test this claim at the 0.01 significance level,
what would be your null and
alternative
hypotheses?
b)
What type of hypothesis test should you conduct (left-, right-, or
two-tailed)?

Past studies have indicated that the percentage of smokers was
estimated to be about 30%. Given the new smoking cessation programs
that have been implemented, you now believe that the percentage of
smokers has reduced. You randomly surveyed 2361 people and found
that 664 smoke. Use a 0.05 significance level to test the claim
that the percentage of smokers has reduced.
a) Identify the null and alternative
hypotheses?
H0H0: Select an answer p = p ≠ p < p >...

It has long been stated that the mean temperature of humans is
98.6 degrees F. However, two researchers currently involved in the
subject thought that the mean temperature of humans is less than
98.6 degrees F. They measured the temperatures of 61 healthy adults
1 to 4 times daily for 3 days, obtaining 275 measurements. The
sample data resulted in a sample mean of 98.2 degrees F and a
sample standard deviation of 1.1 degrees F. Use the P-value
approach...

The blue catfish (Ictalurus Furcatus) is the largest species of
North American catfish. The current world record stands at 143
pounds, which was caught in the John H. Kerr Reservoir (Bugg's
Island Lake) located in Virginia. According to American Expedition,
the average weight of a blue catfish is between 20 to 40 pounds.
Given that the largest blue catfish ever caught was at the John H.
Kerr Reservoir, you believe that the mean weight of the fish in
this reservoir...

The blue catfish (Ictalurus Furcatus) is the largest species of
North American catfish. The current world record stands at 143
pounds, which was caught in the John H. Kerr Reservoir (Bugg's
Island Lake) located in Virginia. According to American Expedition,
the average weight of a blue catfish is between 20 to 40 pounds.
Given that the largest blue catfish ever caught was at the John H.
Kerr Reservoir, you believe that the mean weight of the fish in
this reservoir...

The blue catfish (Ictalurus Furcatus) is the largest species of
North Amercian catfish. The current world record stands at 143
pounds, which was caught in the John H. Kerr Reservoir (Bugg's
Island Lake) located in Virginia. According to Amercian Expedition,
the average weight of a blue catfish is between 20 to 40 pounds.
Given that the largest blue catfish ever caught was at the John H.
Kerr Reservoir, you believe that the mean weight of the fish in
this reservoir...

You wish to test the
claim that the average IQ score is less than 100 at the .005
significance level. You determine the hypotheses are:
Ho: μ=100
H1:μ<100
You take a simple
random sample of 76 individuals and find the mean IQ score is 95.5,
with a standard deviation of 15.1. Let's consider testing this
hypothesis two ways: once with assuming the population standard
deviation is not known and once with assuming that it is known.
Round to three decimal...

You wish to test the claim that the average IQ score is less
than 100 at the .01 significance level. You determine the
hypotheses are: H o : μ = 100 H 1 : μ < 100 You take a simple
random sample of 60 individuals and find the mean IQ score is 98.7,
with a standard deviation of 14.6. Let's consider testing this
hypothesis two ways: once with assuming the population standard
deviation is not known and once with...

You wish to test the claim that the average IQ score is less
than 100 at the .005 significance level. You determine the
hypotheses are: H o : μ = 100 H 1 : μ < 100 You take a simple
random sample of 95 individuals and find the mean IQ score is 95.2,
with a standard deviation of 14.4. Let's consider testing this
hypothesis two ways: once with assuming the population standard
deviation is not known and once with...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 3 minutes ago

asked 37 minutes ago

asked 37 minutes ago

asked 46 minutes ago

asked 47 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago