Question

4.In previous tests, baseballs were dropped 24 ft onto concrete surface, and they bounced an average of 92.84 in. In a test of sample of 40 new balls, the bounce height had a mean of 92.67 in. and a standard deviation of 1.79 in. Use 0.05 significance level to test the claim that the new balls have bounce heights with mean same as 92.84 in. Is this a one tailed or a two tailed test? Write the Null Hypothesis in symbols: Write the Null Hypothesis in words: Write the Alternate Hypothesis in symbols: Write the Alternate Hypothesis in words: Write the decision rule. No need for the bell curve—just write the rule Calculate “Z” (you may copy+paste Minitab results here Write the decision regarding the Null Hypothesis Write your conclusion j)What is the P-value?

Answer 1

Null hypothesis: The mean height of bounce is 92.84 in
Alternate hypothesis: The mean height of bounce is not equals to 92.84 in

H0: mu = 92.84
Ha: mu not equals 92.84

xbar = 92.67, n = 40
s = 1.79

This is two tailed test.

Decision rule,
reject H0 if z < -1.96 or t > 1.96

Test statistic,
z = (xbar - mu)/(s/sqrt(n))
z = (92.67 - 92.84)/(1.79/sqrt(40))
z = -0.6

p-value = 0.5485

Fail to reject H0
There are not significant evidence to conclude that the mean bouncing height is different than 92.84 in