Question

If n=26, ¯xx¯ (x-bar)=50, and s=6, find the margin of error at a 99% confidence level (use at least three decimal places)

Answer #1

)solution

Given that,

= 50

s =6

n = 26

Degrees of freedom = df = n - 1 = 26 - 1 = 25

At 99% confidence level the t is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

t
/2 df = t0.005,25 = **2.787**
( using student t table)

Margin of error = E = t/2,df * (s /n)

= **2.787** * ( 6/
26) = 3.279

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