Salaries of 4747 college graduates who took a statistics course in college have a mean, x overbarx, of $63,000. Assuming a standard deviation, sigmaσ, of $16 comma 37216,372, construct a
9090% confidence interval for estimating the population mean μ.
(Round to the nearest integer as needed.)
Solution :
Given that,
Point estimate = sample mean =
= 63000
Population standard deviation =
= 16372
Sample size = n = 47
Z/2
= 1.645
Margin of error = E = Z/2*
(
/
n)
= 1.645 * (16372 /
47)
= 3928
At 90% confidence interval estimate of the population mean is,
- E <
<
+ E
63000 - 3928 <
< 63000 + 3928
59072 <
< 66928
(59072 , 66928 )
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