The SAT scores of entering freshmen at University X have a N(1200, 90) distribution and the SAT scores of entering freshmen at University Y have a N(1215, 110) distribution. A random sample of 100 freshmen is sampled from each University, with ?̅the sample mean of the 100 scores from University X and ?̅the sample mean of the 100 scores from University Y. The probability that ?̅ is less than 1190 is
If X follows N() then by central limit theorem that sampling distribution of sample mean with sample size : n follows N()
X: The SAT scores of entering freshmen at University X
X follows N(1200, 90)
A random sample of 100 freshmen is sampled from each University, with the sample mean of the 100 scores from University X
Sample size : n = 100
Therefore , sampling distribution of sample mean follows N(1200, 90/) i.e follows N(1200, 9)
The probability that is less than 1190 = P( <1190)
Z-score for 1190 = (1190 - mean)/Standard deviation = (1190-1200)/9 = -10/9=-1.11
P( <1190) = P(Z< -1.11)
From Standard normal tables, P(Z<-1.11) = 0.1335
P( <1190) = P(Z< -1.11) = 0.1335
The probability that is less than 1190 = P( <1190) = 0.1335
The probability that is less than 1190 = 0.1335
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