Use the sample data below to test the hypotheses
H 0: p 1 = p 2 = p 3
H a: Not all population proportions are the same
Populations | |||
Response | 1 | 2 | 3 |
Yes | 150 | 150 | 92 |
No | 100 | 150 | 108 |
where p i is the population proportion of yes responses for population i. Using a .05 level of significance. Use Table 12.4.
a. Compute the sample proportion for each population. Round your answers to two decimal places.
p̄ 1 =
p̄ 2 =
p̄ 3 =
b. Use the multiple comparison procedure to determine which population proportions differ significantly. Use a .05 level of significance. Round p i, pj and difference to two decimal places. Round critical value to four decimal places.
Comparison | p i | p j | Difference | n i | n j | Critical Value | Significant Diff > CV |
1 vs 2 | - Select your answer -YesNoItem 10 | ||||||
1 vs 3 | - Select your answer -YesNoItem 17 | ||||||
2 vs 3 | - Select your answer -YesNoItem 24 |
- Select your answer -1 and 21 and 32 and 3none of themItem 25
a)
p̅1=150/250= | 0.6 |
p̅2=150/300= | 0.5 |
p̅3=92/200 = | 0.46 |
b)
for 2 df and 0.05 level X2 = | 5.9915 |
As Criitcal value =√X2*√(p̅1*(1-p̅1)/n1+p̅2*(1-p̅2)/n2) |
critical val | |||||||
Comparison | pi | pj | |abs diff| | ni | nj | value | significant diff >CV |
1 vs 2 | 0.60 | 0.50 | 0.10 | 250 | 300 | 0.1037 | not significant difference |
1 vs 3 | 0.60 | 0.46 | 0.14 | 250 | 200 | 0.1149 | significant difference |
2 vs 3 | 0.50 | 0.46 | 0.04 | 300 | 200 | 0.1115 | not significant difference |
1 vs 3 are different
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