To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material.
Manufacture | ||
1 | 2 | 3 |
18 | 30 | 24 |
27 | 24 | 18 |
24 | 33 | 27 |
21 | 27 | 21 |
a. Compute the values below (to 2 decimals, if necessary).
Sum of Squares, Error | |
Mean Squares, Error | |
Fisher's LSD Value |
b. Use Fisher's LSD procedure to develop a 95% confidence
interval estimate of the difference between the means for
manufacturer 1 and manufacturer 2. Round to two decimal places.
Enter negative values as negative numbers.
to
Applying one way ANOVA: (use excel: data: data analysis: one way ANOVA: select Array): |
Source | SS | df | MS | F | P value |
Between | 96.000 | 2 | 48.00 | 3.2000 | 0.089 |
Within | 135.000 | 9 | 15.00 | ||
Total | 231.000 | 11 |
a)
sum of sq; error= | 135.00 |
mean square; error= | 15.00 |
critical value of t with 0.05 level and N-k=9 degree of freedom= | tN-k= | 2.262 | |||
Fisher's (LSD) for group i and j =(tN-k)*(sp*√(1/ni+1/nj) = | 6.19 |
b)
95% confidence interval estimate of the difference between the means for manufacturer 1 and manufacturer 2 =(x1-x2) -/+ LSD = -12.19 to 0.19
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