Consider the observed frequency distribution for a set of grouped random variables available below. Perform a chi-square test using a α=0.10 to determine if the observed frequencies follow the normal probability distribution with μ=99 and σ=20.
Click the icon to view the observed frequency distribution.
Random Variable, x | Frequency, fo |
Less than 79 | 10 |
79 to under 99 | 14 |
99 to under 119 | 18 |
119 and more | 8 |
Total | 50 |
State the appropriate null and alternative hypotheses. What is the null hypothesis?
A.H 0 : The mean number of the random variable is not equal to 99.
B.H 0 : The random variable follows the normal probability distribution.
C.H 0 : The mean number of the random variable is equal to 99.
D.H 0 : The random variable does not follow the normal probability distribution.
What is the alternative hypothesis?
A.H 1 : The mean number of the random variable is equal to 99.
B.H 1 : The random variable does not follow the normal probability distribution.
C.H 1: The mean number of the random variable is not equal to 99.
D.H 1 : The random variable follows the normal probability distribution.
Calculate the chi-square test statistic,
X2=
(Round to two decimal places as needed.)
Determine the p-value.
p-value=
(Round to three decimal places as needed.)
State the appropriate conclusion. ▼ Reject OR Do not reject H 0. There is ▼ insufficient OR sufficient evidence to conclude that the random variable does not follow the normal probability distribution.
null hypothesis: Ho:
observed frequencies follow the normal probability distribution with mu= 99 and sigma=20
alternate hypothesis:Ha: observed frequencies does not follow the normal probability distribution with mu= 99 and sigma=20
Chi square Test statistic = 1.141487239
p-value =0.5811
for p value is very high; Do not reject H 0. There is insufficient evidence to conclude that the random variable does not follow the normal probability distribution.
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