Question

Total number of subjects = 36 (3 in each cell) Number of columns (factor 1) =...

Total number of subjects = 36 (3 in each cell)
Number of columns (factor 1) = 3
Number of rows (factor 2) = 4
Total sum of squares = 40
Sum of squares between cells = 16
Sum of squares for factor 1 = 10
Sum of squares for factor 2 = 4

The interaction sum of squares is equal to:

a) 2.

b) 36.

c) 10.

d) 24.

Homework Answers

Answer #1

The interaction sum of squares = 40-(16+10+4) = 10                                                                                    

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Total number of subjects = 36 (3 in each cell) Number of columns (factor 1) =...
Total number of subjects = 36 (3 in each cell) Number of columns (factor 1) = 3 Number of rows (factor 2) = 4 Total sum of squares = 40 Sum of squares between cells = 16 Sum of squares for factor 1 = 10 Sum of squares for factor 2 = 4 The within-cell sum of squares is equal to: a) 10. b) 2. c) 24. d) 36.
The partially complete ANOVA table given here is for a two-factor factorial experiment Source   Df SS...
The partially complete ANOVA table given here is for a two-factor factorial experiment Source   Df SS MS factor A 3 2.25 0.75 Factor B 1 0.95 Interaction 3 0.30 error 16 2.40 0.15 total 6.50 The number of observations collected for this study is   The Sum of Squares for the interaction is equal to The Sum of Squares for the treatments is equal to The number of degrees of freedom for the treatments is equal to The Mean of Squares...
The partially complete ANOVA table given here is for a two-factor factorial experiment Source Df SS...
The partially complete ANOVA table given here is for a two-factor factorial experiment Source Df SS MS factor A 3 2.25 0.75 Factor B 1 0.95 0 Interaction 3 0  0.30 error 16 2.40 0.15 total 0 6.50 0 the number of observations collected for this study is ____ The Sum of Squares for the interaction is equal to _______ The Sum of Squares for the treatments is equal to _______ The number of degrees of freedom for the treatments is...
1. Using the two-way mixed ANOVA, different participants are observed at each level of the between-subjects...
1. Using the two-way mixed ANOVA, different participants are observed at each level of the between-subjects factor, and the same participants are observed across the levels of the within-subjects factor. TRUE OR FALSE 2. A researcher computes two 2 × 2 between-subjects ANOVAs. In Study 1, he observes 8 participants in each cell; in Study 2, he observes 12 participants in each cell. Which study is associated with a larger value for degrees of freedom for the A × B...
True or False Questions: 1. In one-factor ANOVA, the total sum of squares can be separated...
True or False Questions: 1. In one-factor ANOVA, the total sum of squares can be separated into the sum of squares of treatments and sum of square of error. T/F? 2. The mean sum of square of factor over the mean sum of square of error follows F-distribution. T/F? 3. If the mean sum of square of factor over the mean sum of square of error is 1, we should reject null hypothesis. T/F? 4. ANOVA can't be used when...
Use Excel to compute the table with columns for (1) N=number of coins, (2) N/2 =...
Use Excel to compute the table with columns for (1) N=number of coins, (2) N/2 = expected number of heads on average, (3) Sqrt[N]/2 = standard deviation, (4) typical range for number of heads (i.e. average – standard deviation to average + standard deviation), (5) relative width = standard deviation / average. Make rows for N = {10, 100, 1000, 10^4, 10^6, 10^8, … , 10^20, 10^22, 10^24}.
ANOVA Source of Variation SS df MS F p-value Factor A 31,313.49 3 10,437.83 Factor B...
ANOVA Source of Variation SS df MS F p-value Factor A 31,313.49 3 10,437.83 Factor B 23,456.13 2 11,728.07 Interaction 163,204.45 6 27,200.74 Error 90,156.59 36 2,504.35 Total 308,130.66 47 (a) What kind of ANOVA is this? One-factor ANOVA Two-factor ANOVA with replication Two-factor ANOVA without replication (b) Calculate each F test statistic and the p-value for each F test using Excel's function =F.DIST.RT(F,DF1,DF2). (Round your Fcalc values to 3 decimal places and p-values to 4 decimal places.) Source of...
A two-way analysis of variance experiment with no interaction is conducted. Factor A has three levels...
A two-way analysis of variance experiment with no interaction is conducted. Factor A has three levels (columns) and Factor B has six levels (rows). The results include the following sum of squares terms: SST = 390.8 SSA = 238.5 SSE = 69.9 a. Construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, "F" to 3 decimal places.) b. At the 10% significance level, can you...
The calculations for a factorial experiment involving four levels of factor A, three levels of factor...
The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following data: SST=286, SSA=24, SSB=22, SSAB=185.. Set up the ANOVA table and test for significance using a=.05. Show entries to 2 decimals, if necessary. If the answer is zero enter “0”. Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Factor A Factor B Interaction Error Total The -value for Factor A is...
A two-way analysis of variance experiment with no interaction is conducted. Factor A has three levels...
A two-way analysis of variance experiment with no interaction is conducted. Factor A has three levels (columns) and Factor B has seven levels (rows). The results include the following sum of squares terms: SST = 346.9 SSA = 196.3 SSE = 79.0 a. Construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, "F" to 3 decimal places.) Source SS df MS F p-value Rows Columns...