Question

Total number of subjects = 36 (3 in each cell)

Number of columns (factor 1) = 3

Number of rows (factor 2) = 4

Total sum of squares = 40

Sum of squares between cells = 16

Sum of squares for factor 1 = 10

Sum of squares for factor 2 = 4

The interaction sum of squares is equal to:

a) 2.

b) 36.

c) 10.

d) 24.

Answer #1

The interaction sum of squares = 40-(16+10+4) = 10

Total number of subjects = 36 (3 in each cell)
Number of columns (factor 1) = 3
Number of rows (factor 2) = 4
Total sum of squares = 40
Sum of squares between cells = 16
Sum of squares for factor 1 = 10
Sum of squares for factor 2 = 4
The within-cell sum of squares is equal to:
a) 10.
b) 2.
c) 24.
d) 36.

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F
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30
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41
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50.000
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2.000
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4
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40
12.500
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P
Q
TC
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$36
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$20
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