Question

In a survey of

1001

adults, a polling agency asked, "When you retire, do you think you will have enough money to live comfortably or not. Of the

10011

surveyed,

522

stated that they were worried about having enough money to live comfortably in retirement. Construct a

9090%

confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement.

Answer #1

Sample proportion = 522 / 1001 = 0.521

90% confidence interval for p is

- Z * sqrt ( ( 1 - ) / n) < p < + Z * sqrt ( ( 1 - ) / n)

0.521 - 1.645 * sqrt( 0.521 * 0.479 / 1001 ) < p < 0.521 + 1.645 * sqrt( 0.521 * 0.479 / 1001 )

0.495 < p < 0.547

90% CI is **( 0.495 , 0.547 )**

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