Question

according to Nielsen media research 25.8% of American men aged 18 to 34 watch television during prime time in July 2004 assume that this percentage is true for the current population of men aged 18 to 34. let ^p be The proportion of men who watch television during prime time in a random sample of 225 men aged 18 to 34 find the probability that the value of ^P is greater than 0.221.

Answer 1

p = 0.258

n = 225

= p = 0.258

= sqrt(p(1 - p)/n)

      = sqrt(0.258 * (1 - 0.258)/225)

       = 0.0292

P( > 0.221)

= P(( - )/ > (0.221 - )/)

= P(Z > (0.221 - 0.258)/0.0292)

= P(Z > -1.27)

= 1 - P(Z < -1.27)

= 1 - 0.1020

= 0.8980