(a) 203 (b) 329 (c) 247 (d) 396 (e) 289
Solution :
Given that,
= 0.25
1 - = 1 - 0.25 = 0.75
margin of error = E = 0.05
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
Sample size = n = (Z/2 / E)2 * * (1 - )
= (1.645 * 0.05)2 * 0.25 * 0.75
= 202.95
Sample size = 203 (rounded)
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