A genetic experiment involving peas yielded one sample of offspring consisting of 442 green peas and 123 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution
This is the two tailed test .
The null and alternative hypothesis is
H0 : p = 0.26
Ha : p 0.26
= x / n = 123 / 442 = 0.2783
P0 = 0.26
1 - P0 = 0.74
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
= 0.2783 - 0.26 / [(0.26 * 0.74) / 442]
P(z > 0.876) = 1 - P(z < 0.876) = 0.1905
P-value = 0.381
Fail to reject the null hypothesis .
There is not sufficient evidence that the 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow .
Get Answers For Free
Most questions answered within 1 hours.