In a recent poll, 801 adults were asked to identify their favorite seat when they fly, and 476 of them chose a window seat. Use a 0.05 significance level to test the claim that the majority of adults prefer window seats when they fly. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
Which of the following is the hypothesis test to be conducted?
A.
Upper H 0 : p greater than 0.5H0: p>0.5
Upper H 1 : p equals 0.5H1: p=0.5
B.
Upper H 0 : p equals 0.5H0: p=0.5
Upper H 1 : p not equals 0.5H1: p≠0.5
C.
Upper H 0 : p not equals 0.5H0: p≠0.5
Upper H 1 : p equals 0.5H1: p=0.5
D.
Upper H 0 : p equals 0.5H0: p=0.5
Upper H 1 : p greater than 0.5H1: p>0.5
E.
Upper H 0 : p less than 0.5H0: p<0.5
Upper H 1 : p equals 0.5H1: p=0.5
F.
Upper H 0 : p equals 0.5H0: p=0.5
Upper H 1 : p less than 0.5H1: p<0.5
What is the test statistic?
z=___
(Round to two decimal places as needed.)
What is the P-value?
P-value = ___
(Round to three decimal places as needed.)
What is the conclusion about the null hypothesis?
A.Reject the null hypothesis because the P-value is less than or equal to the significance level, α.
B.Reject the null hypothesis because the P-value is greater than the significance level, α.
C.Fail to reject the null hypothesis because the P-value is greater than the significance level, α.
D.Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α.
What is the final conclusion?
A.There is not sufficient evidence to support the claim that the majority of adults prefer window seats when they fly.
B.There is sufficient evidence to support the claim that the majority of adults prefer window seats when they fly.
C.There is sufficient evidence to warrant rejection of the claim that the majority of adults prefer window seats when they fly.
D.There is not sufficient evidence to warrant rejection of the claim that the majority of adults prefer window seats when they fly.
Solution :
This is the two tailed test .
The null and alternative hypothesis is
H0 : p = 0.5
Ha : p 0.5
= x / n = 476 / 801 = 0.5943
P0 = 0.5
1 - P0 = 0.5
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
= 0.5943 - 0.5 / [(0.5 * 0.5) / 801]
= 5.33
P(z > 5.33) = 1 - P(z < 5.33) = 0
P-value = 0
= 0.05
P-value <
A)Reject the null hypothesis because the P-value is less than or equal to the significance level, .
C)There is sufficient evidence to warrant rejection of the claim that the majority of adults prefer window seats when they fly.
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