A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of 6724 with a mean life of 645 minutes. If the claim is true, in a sample of 152 batteries, what is the probability that the mean battery life would differ from the population mean by more than 8 minutes? Round your answer to four decimal places.
Solution :
Given that ,
mean = = 645
standard deviation = = 82
P(637 < x < 653) = P((637 - 645)/ 82) < (x - ) / < (653 - 645 ) / 82) )
= 1 - (P(-0.098 < z < 0.098) )
= 1 - (P(z < 0.098) - P(z < -0.098))
= 1 - (0.5390 - 0.4610)
= 1 - 0.0780
= 0.9220
Probability = 0.9220
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