You just measured the amount of yogurt in 36 6 ounce cups (which we assume is μ). Given that σ=.42 ounces, what is the probability that the sample average of the 36 cups measured was less than 5.8 ounces?
Solution :
Given that ,
mean = = 6
standard deviation = = 0.42
n = 36
= 6
= / n = 0.42 / 36 = 0.07
P( < 5.8) = P(( - ) / < (5.8 - 6) / 0.07)
= P(z < -2.86)
= 0.0021
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