A simple random sample of 60 items resulted in a sample mean of 89. The population standard deviation is 12.
a. Compute the 95% confidence interval for the population mean (to 1 decimal).
b. Assume that the same sample mean was obtained from a sample of 120 items. Provide a 95% confidence interval for the population mean (to 2 decimals).
Confidence interval = Z*
= 89
= 12
For 95% confidence level, Z* = 1.96
a) Sample size, n = 60
Confidence interval = 89 1.96 x
= 89 3.0
= [86.0, 92.0]
b) Sample size, n = 120
Confidence interval = 89 1.96 x
= 89 2.15
= [86.85, 91.15]
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