Six hunters saw a fox and fired at the same time. Suppose that each of the hunters can hit the fox in this distance in 1 out of 3 cases. What is the probability that the fox will be hunted down?
6 hunters saw a fox and fired at the same time.
Suppose that each of the hunters can hit the fox in the given distance, in 1 out of 3 cases.
This means, each hunter has a chance 1/3, of hunting the fox down.
So, the chance that any of these 6 hunters cannot hunt the fox down, is 1-1/3, ie. 2/3.
Now, we have to find the probability that the fox will be hunted down.
This event is complementary to the event that the fox won't be hunted down; which means all 6 hunters miss their shots.
So,
P(The fox will be hunted down)
=1-P(The fox survives)
=1-P(All 6 hunters miss)
So, the probability that the fox will be hunted down, is 0.9122.
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