Question

The one sample t-test from a sample of n = 19 observations for the two-sided (two-tailed) test of

H0: μ = 6

H1: μ ≠ 6

Has a t test statistic value = 1.93. You may assume that the original population from which the sample was taken is symmetric and fairly Normal.

Computer output for a t test:

One-Sample T: Test of mu = 6 vs not = 6

N Mean StDev SE Mean 95% CI T P

19 6.200
0.451
0.103 (5.983,
6.417) **1.93
0.069**

**Based on this information... Also, can you please
explain?**

a. We would fail to reject the null hypothesis at α = 0.05.

b. We would reject the null hypothesis at α = 0.01.

c. We would fail to reject the null hypothesis at α = 0.1.

Answer #1

Consider the computer output below.
Two-Sample T-Test and CI
Sample
N
Mean
StDev
SE Mean
1
15
54.79
2.13
0.55
2
20
58.60
5.28
1.2
Difference = μ1-μ2
Estimate for difference: –3.91
95% upper bound for difference: ?
T-test of difference = 0 (vs <): T-value = -2.93
P-value = ?
DF = ?
(a) Fill in the missing values. Use lower and upper bounds for
the P-value. Suppose that the hypotheses are H0: μ1-μ2=0 versus H1:
μ1-μ2<0.
Enter your...

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