Examine the following hypothesis test when n equals=16, s equals= 11, and x overbar equals = 16
H0: mu μ |
greater than or equals ≥ |
18 18 |
HA: mu μ |
less than < |
18 18 |
alpha α |
equals = |
0.10 0.10 |
a. State the decision rule in terms of the critical value of the test statistic.
b. State the calculated value of the test statistic.
c. State the conclusion.
a)
t critical value at 15 df with 0.10 significance level = -1.341
Decision rule = Reject H0 if test statistics < -1.341
b)
Test statistics
t = - / S / sqrt(n)
= 16 - 18 / 11 / sqrt(16)
= -0.73
This is test statistics value.
c)
Since test statistics falls in non-rejection region, we do not have sufficient evidence to reject H0.
We conclude at 0.10 level that we fail to support the claim.
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