Construct the indicated confidence interval for the population mean mu using the t-distribution. Assume the population is normally distributed.
c=0.95, x bar=12.2, s=0.53, n=19
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Solution :
Given that,
Point estimate = sample mean = = 12.2
sample standard deviation = s = 0.53
sample size = n = 19
Degrees of freedom = df = n - 1 = 18
t /2,df = 2.101
Margin of error = E = t/2,df * (s /n)
= 2.101 * (0.53 / 19)
Margin of error = E = 0.26
The 95% confidence interval estimate of the population mean is,
- E < < + E
12.2 - 0.26 < < 12.2 + 0.26
11.94 < < 12.46
(11.94 , 12.46)
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