A recent study of undergraduates looked at gender differences in dieting trends. There were 181 women and 103 men who participated in the survey. The table below summarizes whether a student tried a low-fat diet or not by gender:
Gender | ||||
---|---|---|---|---|
Tried low-fat diet | Women | Men | ||
Yes | 38 | 8 | ||
No |
(a) Fill in the missing cells of the table.
Gender | ||||
---|---|---|---|---|
Tried low-fat diet | Women | Men | ||
Yes | 38 | 8 | ||
No |
(b) Summarize the data numerically. What percent of each gender has
tried low-fat diets? (Round your answers to two decimal
places.)
women | % |
men | % |
(c) Test that there is no association between gender and the
likelihood of trying a low-fat diet. (Round your
χ2 to three decimal places, and round your
P-value to four decimal places.)
χ2 | = | |
df | = | |
P-value | = |
a)
Oi | Women | Men |
Yes | 38 | 8 |
No | 143 | 95 |
b)
women | 20.99% |
men | 7.77% |
c)applying chi square test:
Expected | Ei=row total*column total/grand total | Women | Men | Total |
Yes | 29.32 | 16.68 | 46 | |
No | 151.68 | 86.32 | 238 | |
total | 181 | 103 | 284 | |
chi square χ2 | =(Oi-Ei)2/Ei | Women | Men | Total |
Yes | 2.5718 | 4.5193 | 7.091 | |
No | 0.4971 | 0.8735 | 1.371 | |
total | 3.069 | 5.393 | 8.462 |
X2 =8.462
df=1
p value =0.0036
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