Suppose x has a distribution with μ = 80 and σ = 11.
Find P(76 ≤ x ≤ 81). (Round your answer to four decimal places.)
Solution :
Given that ,
mean = = 80
standard deviation = = 11
P(76 x 81 )
= P[(76-80/11) (x - ) / (81-80 /11)]
= P(-4/11 z 1/11)
= P( -0.36 z 0.09)
= P(z 0.09) - P(z -0.36)
= 0.5359 - 0.3594
Probability = 0.1765
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