Question

Suppose *x* has a distribution with *μ* = 80 and
*σ* = 11.

Find *P*(76 ≤ *x* ≤ 81). (Round your answer to
four decimal places.)

Answer #1

Solution :

Given that ,

mean = = 80

standard deviation = = 11

P(76 x 81 )

= P[(76-80/11) (x - ) / (81-80 /11)]

= P(-4/11 z 1/11)

= P( -0.36 z 0.09)

= P(z 0.09) - P(z -0.36)

= 0.5359 - 0.3594

**Probability = 0.1765**

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to four decimal places.)
μx =
σ x =
P(11 ≤ x (x bar) ≤ 13) =
(b) If a random sample of size n = 63 is drawn, find μx, σ x and
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Suppose x has a distribution with μ = 24 and
σ = 11.
1. If random samples of size n = 16 are selected, can
we say anything about the x distribution of sample
means?
2. If the original x distribution is normal, can
we say anything about the x distribution of random samples
of size 16?
3. Find P(20 ≤ x ≤ 25). (Round your answer to
four decimal places.)
___________________

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(a) If a random sample of size n = 41 is drawn, find μx, σ x
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probability to four decimal places.)
μx =
σ x =
P(29 ≤ x ≤ 31) =
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and P(29 ≤ x ≤...

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σ = 22.
(a) If a random sample of size n = 40 is drawn, find
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σx to two decimal places and the
probability to four decimal places.)
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σx =
P(25 ≤ x ≤ 27) =
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σx...

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(a) If random samples of size n = 16 are selected, can
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No, the sample size is too small.Yes, the x
distribution is normal with mean μx =
75 and σx =
0.5. Yes, the x distribution is
normal with mean μx = 75 and
σx = 2.Yes, the x
distribution is normal with mean μx =
75...

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