Suppose x has a distribution with μ = 80 and σ = 11.
Find P(76 ≤ x ≤ 81). (Round your answer to four decimal places.)
Solution :
Given that ,
mean =
= 80
standard deviation =
= 11
P(76
x
81 )
= P[(76-80/11)
(x -
) /
(81-80 /11)]
= P(-4/11
z
1/11)
= P( -0.36
z
0.09)
= P(z
0.09) - P(z
-0.36)
= 0.5359 - 0.3594
Probability = 0.1765
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