Given that mea = 150 and standard deviation = 10
sample size is n =100
standard deviation for the sample = sd/sqrt(n) = 10/sqrt(100) = 10/10 = 1
we have to find P(130<X<170)
using the formula
P(130<X<170) = P((x-mean)/s<z<(y-mean)/s)
= P((130-150)/1<z<(170-150)/1)
= P(-20<z<20)
= 1.0 (because 99.7% of data fall withiin 3 standard deviation and we are finding the probability of data falling between -20 to 20 standard deviation)
This means that for a sample of 100 oranges, 100% of the oranges wil weigh between 130 and 170 grams
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