A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 60 cookies. The mean is 23.05 and the standard deviation is 2.75. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.
Chi square critical values at 0.20 level with 59 df = 45.577 , 73.279
80% confidence interval for is
Sqrt [ (n-1) S2 / /2 ] < < Sqrt [ (n-1) S2 / 1-/2 ]
Sqrt [ 59 * 2.752 / 73.279 ] < < Sqrt [ 59 * 2.752 / 45.577 ]
2.4675 < < 3.1289
80% CI is ( 2.4675 , 3.1289 )
Get Answers For Free
Most questions answered within 1 hours.