Let X be the variable denoting the liters of blood an adult has.
X N(6.2,0.32) ,
where = E[X] = 6.2 and 2 = Var[X] = 0.32 = 0.09
Z =( X - ) / N(0,1)
Pr[ X < 5.4 ] = Pr[ (X - ) / < (5.4-6.2)/0.3 ] = Pr[Z < -2.6667 ] =
= 1 -
= 1 - 0.6064199
= 0.3935801 0.3936 [ correct up to 4 decimal places ]
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