A random sample of n1 = 52 men and a random sample of n2 = 48 women were chosen to wear a pedometer for a day.
The men’s pedometers reported that they took an average of 8,342 steps per day, with a standard deviation of
s1 = 371 steps.
The women’s pedometers reported that they took an average of 8,539 steps per day, with a standard deviation of s2 = 214 steps.
We want to test whether men and women have different mean step counts.
The null hypothesis is H0: μ1 = μ2. The alternative hypothesis is Ha: μ1 μ2 . (Fill in the blank to show the appropriate relation between μ1 and μ2.)
The degrees of freedom for the test are
The P-value for the test is .
The decision is to (reject or not reject) the null hypothesis, at the 0.05 level of significance.
To Test :-
H0 :-
H1 :-
Test Statistic :-
t = -3.2829
Test Criteria :-
Reject null hypothesis if
DF = 82
Result :- Reject Null Hypothesis
Decision based on P value
P - value = P ( t > 3.2829 ) = 0.0015
Reject null hypothesis if P value <
level of significance
P - value = 0.0015 < 0.05 ,hence we reject null hypothesis
Conclusion :- Reject null hypothesis
The decision is to ( reject ) the null hypothesis, at the 0.05 level of significance.
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