Question

Random sampling from four normally distributed populations produced the following data: (You may find it useful...

Random sampling from four normally distributed populations produced the following data: (You may find it useful to reference the F table.)

Treatments
A B C D
−12 −20 −5 −20
−20 −9 −18 −20
−11 −13 −17 −20
−19 −7
−16

Click here for the Excel Data File

a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

b. Calculate SSTR and MSTR. (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)

c. Calculate SSE and MSE. (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)

d. Specify the competing hypotheses in order to determine whether some differences exist between the population means.

  • H0: μA = μB = μC; HA: Not all population means are equal.

  • H0: μAμBμC; HA: Not all population means are equal.

  • H0: μAμBμC; HA: Not all population means are equal.

e-1. Calculate the value of the F(df1, df2) test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)

e-2. Find the p-value.

  • 0.05 p-value < 0.10
  • 0.01 p-value < 0.025
  • p-value 0.10
  • 0.025 p-value < 0.05
  • p-value < 0.01

f. At the 10% significance level, what is the conclusion to the test?

  • Do not reject H0 since the p-value is not less than significance level

  • Reject H0 since the p-value is less than significance level

  • Reject H0 since the p-value is not less than significance level

  • Do not reject H0 since the p-value is less than significance level



g. Interpret the results at α = 0.10.

  • We conclude that some means differ.

  • We cannot conclude that some means differ.

  • We cannot conclude that all means differ.

  • We cannot conclude that population mean C is greater than population mean A.

Homework Answers

Answer #1

applying one way ANOVA

Source of Variation SS df MS F P-value F crit
Between Groups 105.1167 3 35.03889 1.383362 0.299223 3.587434
Within Groups 278.6167 11 25.32879
Total 383.7333 14

a) grand mean =-15.13

b)SSTR =105.1167

and MSTR =35.0389

c)

SSE =278.6167

MSE =25.3288

d)

H0: μA = μB = μC; HA: Not all population means are equal

e-1 )F =1.383

e-2)

p-value > 0.10

f)

Do not reject H0 since the p-value is not less than significance leve

g)

We cannot conclude that some means differ.

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