Question

Random sampling from four normally distributed populations produced the following data: (You may find it useful...

Random sampling from four normally distributed populations produced the following data: (You may find it useful to reference the F table.)

Treatments
A B C D
−12 −20 −5 −20
−20 −9 −18 −20
−11 −13 −17 −20
−19 −7
−16

Click here for the Excel Data File

a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

b. Calculate SSTR and MSTR. (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)

c. Calculate SSE and MSE. (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)

d. Specify the competing hypotheses in order to determine whether some differences exist between the population means.

  • H0: μA = μB = μC; HA: Not all population means are equal.

  • H0: μAμBμC; HA: Not all population means are equal.

  • H0: μAμBμC; HA: Not all population means are equal.

e-1. Calculate the value of the F(df1, df2) test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)

e-2. Find the p-value.

  • 0.05 p-value < 0.10
  • 0.01 p-value < 0.025
  • p-value 0.10
  • 0.025 p-value < 0.05
  • p-value < 0.01

f. At the 10% significance level, what is the conclusion to the test?

  • Do not reject H0 since the p-value is not less than significance level

  • Reject H0 since the p-value is less than significance level

  • Reject H0 since the p-value is not less than significance level

  • Do not reject H0 since the p-value is less than significance level



g. Interpret the results at α = 0.10.

  • We conclude that some means differ.

  • We cannot conclude that some means differ.

  • We cannot conclude that all means differ.

  • We cannot conclude that population mean C is greater than population mean A.

Homework Answers

Answer #1

applying one way ANOVA

Source of Variation SS df MS F P-value F crit
Between Groups 105.1167 3 35.03889 1.383362 0.299223 3.587434
Within Groups 278.6167 11 25.32879
Total 383.7333 14

a) grand mean =-15.13

b)SSTR =105.1167

and MSTR =35.0389

c)

SSE =278.6167

MSE =25.3288

d)

H0: μA = μB = μC; HA: Not all population means are equal

e-1 )F =1.383

e-2)

p-value > 0.10

f)

Do not reject H0 since the p-value is not less than significance leve

g)

We cannot conclude that some means differ.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of five observations from three normally distributed populations produced the following data: (You...
A random sample of five observations from three normally distributed populations produced the following data: (You may find it useful to reference the F table.) Treatments A B C 23 24 29 16 17 31 31 17 27 17 27 16 28 30 16 x−Ax−A = 23.0 x−Bx−B = 23.0 x−Cx−C = 23.8 s2AsA2 = 43.5 s2BsB2 = 34.5 s2CsC2 = 52.7 a. Calculate the grand mean. (Round intermediate calculations to at least 4 decimal places and final answer to...
A random sample of five observations from three normally distributed populations produced the following data: (You...
A random sample of five observations from three normally distributed populations produced the following data: (You may find it useful to reference the F table.) Treatments A B C 15 22 17 23 28 29 31 18 24 32 15 23 23 25 27 x−Ax−A = 24.8 x−Bx−B = 21.6 x−Cx−C = 24.0 s2AsA2 = 48.2 s2BsB2 = 27.3 s2CsC2 = 21.0 a. Calculate the grand mean. (Round intermediate calculations to at least 4 decimal places and final answer to...
A random sample of five observations from three normally distributed populations produced the following data: (You...
A random sample of five observations from three normally distributed populations produced the following data: (You may find it useful to reference the F table.) Treatments A B C 25 17 22 25 19 26 27 25 26 32 18 30 18 17 27 x−Ax−A = 25.4 x−Bx−B = 19.2 x−Cx−C = 26.2 s2AsA2 = 25.3 s2BsB2 = 11.2 s2CsC2 = 8.2 Click here for the Excel Data File a. Calculate the grand mean. (Round intermediate calculations to at least...
An analysis of variance experiment produced a portion of the accompanying ANOVA table. (You may find...
An analysis of variance experiment produced a portion of the accompanying ANOVA table. (You may find it useful to reference the F table.) a. Specify the competing hypotheses in order to determine whether some differences exist between the population means. H0: μA = μB = μC = μD; HA: Not all population means are equal. H0: μA ≥ μB ≥ μC ≥ μD; HA: Not all population means are equal. H0: μA ≤ μB ≤ μC ≤ μD; HA: Not...
Consider the following competing hypotheses and accompanying sample data drawn independently from normally distributed populations. (You...
Consider the following competing hypotheses and accompanying sample data drawn independently from normally distributed populations. (You may find it useful to reference the appropriate table: z table or t table) H0: μ1 − μ2 = 0 HA: μ1 − μ2 ≠ 0 x−1x−1 = 75 x−2x−2 = 79 σ1 = 11.10 σ2 = 1.67 n1 = 20 n2 = 20 a-1. Calculate the value of the test statistic. (Negative values should be indicated by a minus sign. Round all intermediate...
Consider the following competing hypotheses and accompanying sample data drawn independently from normally distributed populations. (You...
Consider the following competing hypotheses and accompanying sample data drawn independently from normally distributed populations. (You may find it useful to reference the appropriate table: z table or t table) H0: μ1 − μ2 = 0 HA: μ1 − μ2 ≠ 0 x−1x−1 = 57 x−2x−2 = 63 σ1 = 11.5 σ2 = 15.2 n1 = 20 n2 = 20 a-1. Calculate the value of the test statistic. (Negative values should be indicated by a minus sign. Round all intermediate...
Consider the following competing hypotheses and accompanying sample data. (You may find it useful to reference...
Consider the following competing hypotheses and accompanying sample data. (You may find it useful to reference the appropriate table: z table or t table) H0: p1 − p2 ≥ 0 HA: p1 − p2 < 0 x1 = 250 x2 = 275 n1 = 400 n2 = 400 a. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal...
Consider the following competing hypotheses and accompanying sample data drawn independently from normally distributed populations. (You...
Consider the following competing hypotheses and accompanying sample data drawn independently from normally distributed populations. (You may find it useful to reference the appropriate table: z table or t table) H0: μ1 − μ2 = 0 HA: μ1 − μ2 ≠ 0 x−1x−1 = 68 x−2x−2 = 80 σ1 = 12.30 σ2 = 1.68 n1 = 15 n2 = 15 a-1. Calculate the value of the test statistic. (Negative values should be indicated by a minus sign. Round all intermediate...
Consider the following data drawn independently from normally distributed populations: (You may find it useful to...
Consider the following data drawn independently from normally distributed populations: (You may find it useful to reference the appropriate table: z table or t table) x−1x−1 = 34.4 x−2x−2 = 26.4 σ12 = 89.5 σ22 = 95.8 n1 = 21 n2 = 23 a. Construct the 90% confidence interval for the difference between the population means. (Negative values should be indicated by a minus sign. Round all intermediate calculations to at least 4 decimal places and final answers to 2...
A random sample of five observations from three normally distributed populations produced the following data: (You...
A random sample of five observations from three normally distributed populations produced the following data: (You may find it useful to reference the F table.) Treatments A B C 31 29 23 29 25 20 22 28 21 31 15 16 31 17 23 x−A = 28.8 x−B = 22.8 x−C = 20.6 s2A = 15.2 s2B = 41.2 s2C = 8.3 Click here for the Excel Data File a. Calculate the grand mean. (Round intermediate calculations to at least...